This reaction works much like the selectivity within amide enolate formation, where the enolate forms in the Z formation where the R group of the enolate is eclipsed by the carbonyl. And this reaction here causes the Evans imide to form the Z enolate selectively due to the lithium metal being an oxophilic agent to both of the carbonyls there, making sure that the bond between the N and the alpha C of the carbonyl doesn't rotate. Now this molecule is ready to be put to use in an enolate reaction.
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